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Chapter 8 · Kerala SSLC Class 10 Maths

Tangents

Two ways to learn — a crisp formula reference, or a story that makes the geometry click.

Tangent ⊥ radiusEqual tangent lengthsTangent-chord angleExternal point
Kerala SSLCClass 10MathsChapter 8 — Tangents11 min read

A story that builds each theorem naturally.

How story mode works

Each scene is a real situation that naturally reveals a tangent theorem. Read the story, then tap "The Maths" to see the formal statement.

1

A Ball Rolling Against a Wall — Tangent ⊥ Radius

Picture a perfectly round football resting against a flat wall. The wall touches the ball at exactly one point — the point of contact. Now draw an imaginary line from the centre of the ball to that contact point.

Physics teacher

The wall must be perpendicular to that radius. If it were tilted even slightly, the ball would either go through the wall or not touch it. A tangent can only exist when it is at exactly 90° to the radius at the contact point.

This is not just intuition — it is a theorem. The radius OT is always perpendicular to the tangent PT at the point of contact T.

This right angle is the key to every tangent calculation. It lets you apply Pythagoras on triangle OTP.
2

Two Rubber Bands from a Point — Equal Tangent Lengths

Stretch two rubber bands from the same pin on a table, each wrapped around a circular tin. No matter how you place the tin, both rubber bands that leave from the same pin and just touch the tin are always the same length.

Student

Is that always true? It feels like it could be slightly different each time.

Teacher

Always. And we can prove it. Both triangles — pin to centre to contact point A, and pin to centre to contact point B — are congruent.

In △OAP and △OBP:

OA = OB (radii, same circle)

OP = OP (common side)

∠OAP = ∠OBP = 90° (tangent ⊥ radius)

∴ △OAP ≅ △OBP (RHS)

∴ PA = PB

The two tangent lengths from any external point are always equal. This fact is used constantly in SSLC problems.

3

The Sliding Ruler — Tangent-Chord Angle Theorem

Place a ruler as a tangent touching a circle at point T. Now draw a chord TC inside the circle. The angle the chord makes with the tangent on one side equals the angle that TC subtends in the opposite (alternate) segment of the circle.

Student

So the angle at the edge — between the tangent and the chord — equals an angle sitting deep inside the circle on the other side?

Teacher

Exactly. Slide the ruler (change the tangent direction) and both angles change together, always staying equal. This is the alternate segment theorem.

If the angle in the alternate segment is 65°, then the angle between the tangent and the chord is also 65°.

The two-tangent angle relationship: if PA and PB are tangents from external P, then ∠APB + ∠AOB = 180°. The angle at P and the central angle are supplementary.

The big picture

Every tangent question uses one of three facts. Know which fact to reach for and the rest is substitution.

Q

Need to find tangent length?

PT = √(OP² − r²) (Pythagoras on OT ⊥ PT)

Q

Two tangents from the same point?

PA = PB (equal tangent lengths)

Q

Angle between tangent and chord?

∠(tangent,chord) = ∠ in alternate segment

Q

Angle between two tangents?

∠APB + ∠AOB = 180°

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